View Source: FizzBuzz

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I read this [blog posting on a trivial programming test|http://imranontech.com/2007/01/24/using-fizzbuzz-to-find-developers-who-grok-coding/] at two in the morning and I got worried: was I an actual programmer?  Thus I decided to implement ~FizzBuzz in bash 3:

<verbatim>
for i in {1..100}
do
  ([ $(($i % 15)) -eq 0 ] && echo FizzBuzz ) || \
  ([ $(($i % 3)) -eq 0 ] && echo Fizz ) || \
  ([ $(($i % 5)) -eq 0 ] && echo Buzz ) || \
  echo $i
done
</verbatim>

A few thoughts:

# Note the use of the new bash 3 builtin iterator <code>{1..100}</code> to generate the list instead of using a counter variable, seq, or jot.
# Note also the use of bash builtin arithmetic evaluation instead of bc or expr.
# I wrote this in the one line style with conditional operators instead of branching.  For some reason I am more comfortable in that style.
# Is there a way to make the return value of a math operation be the mathematical result?  I couldn't think of one offhand.  That leads to the awkward <code>~[ x -eq 0 ~]</code> construct.  I suspect that could be replaced with a combination of expr and eval.

I'd like to hear if anyone can write this in a more compact and/or elegant fashion in bash 3.  However, I'm not really interested in going the obfuscated code route - what's the most compact way you can write this script that is still readable and elegant?

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